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Another conditional syntax question
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Another conditional syntax question

mrowton
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Joined: Feb 19, 2004
Location: Michigan
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Posted 08/12/07 - 08:08 AM:

I can't get the parentids to work in the below conditional on the "displaylinks" template. I've tried "{CATPARENTIDS}" and just "parentids".

<IF {CATID} is 1><a href="http://www.webmastersite.net/forums/1.php">One</a> 
 
<OTHERWISE IF {CATID} is 2><a href="http://www.webmastersite.net/forums/2.php">Two</a> 
 
<OTHERWISE IF {CATID} is 3 OR {CATPARENTIDS} LIKE '%3%'><a href="http://www.webmastersite.net/forums/3.php">Third</a> 
 
<OTHERWISE> 
 
<a href="http://www.webmastersite.net/forums/4.php">Fourth</a> 
 
</IF>

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Paul
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Joined: Dec 21, 2001
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Posted 08/12/07 - 07:58 PM:	#2
Template conditionals have nothing to do with MySQL, so don't type MySQL queries in them. If you're trying to find whether a category is beneath category number three, use {CATISBENEATH[3]}.
"Do things you love doing, because then it ain't work. Don't do something you don't really enjoy, because you're never going to work hard enough at it." - Bob Young, founder of Red Hat

mrowton
Forum Regular

Usergroup: Customer
Joined: Feb 19, 2004
Location: Michigan
Total Topics: 59
Total Posts: 189

Last Blog:

Posted 08/13/07 - 04:45 PM:	#3
perfectomundo!
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